-50=-16x^2+107x

Solution for -50=-16x^2+107x equation:

-50=-16x^2+107x

We move all terms to the left:

-50-(-16x^2+107x)=0

We get rid of parentheses

16x^2-107x-50=0

a = 16; b = -107; c = -50;
Δ = b2-4ac
Δ = -1072-4·16·(-50)
Δ = 14649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-107)-\sqrt{14649}}{2*16}=\frac{107-\sqrt{14649}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-107)+\sqrt{14649}}{2*16}=\frac{107+\sqrt{14649}}{32}
$